Combinations can we have from a sample of elements from a set of distinct objects where order does matter and replacements are not allowed Practice Problem
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How many combinations can we have from:
r elements from n distinct objects
where order does matter and
replacements are not allowed?
Combinations with Replacment Formula
CR(n,r) =
(n + r - 1)!
r! (n - 1)!
Plug in n = 10 and r = 5, we get:
CR(10,5) =
(10 + 5 - 1)!
5!(10 - 1)!
CR(10,5) =
14!
5!(9)!
Calculate 14!
14! = 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
14! = 87178291200
Calculate 5!
5! = 5 x 4 x 3 x 2 x 1
5! = 120
Calculate 9!
9! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
9! = 362880
Plug in factorial values:
CR(10,5) =
14!
5!(9)!
CR(10,5) =
87178291200
120(362880)
CR(10,5) =
87178291200
43545600
CR(10,5) = 2002
You have 2 free calculationss remaining
Excel or Google Sheets formula:
Excel or Google Sheets formula:=FACT(10+5-1)/FACT(5)(FACT(10 - 1)
What is the Answer?
CR(10,5) = 2002
How does the Combinations with Replacement Calculator work?
Free Combinations with Replacement Calculator - Calculates the following: How many combinations can we have from a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed? This calculator has 2 inputs.
What 1 formula is used for the Combinations with Replacement Calculator?
What 3 concepts are covered in the Combinations with Replacement Calculator?
combination
a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter nPr = n!/r!(n - r)!
combinations with replacement
factorial
The product of an integer and all the integers below it