27^2/3

-243^1/5

w^7/4

What is the 5th root of 243

4^1/2*4^5/2

Simplify the rational exponent 27

That is equivalent to saying we take the cThe rule of fractional exponents states that a^{b/c}is evaluated as follows:

a^{b/c}= (^{c}√a)^{b}

In this case, a = 27, b = 2, and c = 5

There is no integer answer for this problem since root 5 of 27 does not exist as an integer