1 multiplied by b squared multiplied by c squared b squared means we raise b to the power of 2: b^2 c squared means we raise c to the power of 2: c^2 b squared multiplied by c squared b^2c^2 1 multiplied by b squared multiplied by c squared means we multiply 1 by b^2c^2 1b^2c^2 Multiplying by 1 can be written by [U][I]removing[/I][/U] the 1 since it's an identity multiplication: [B]b^2c^2[/B]

3^14/27^4 = ? Understand that 27 = 3^3. Rewriting this, we have: 3^14/(3^3)^4 Exponent identity states (a^b)^c = a^bc, so we have: 3^14/3^12 Simplifying, we have: 3^(14 - 12) = 3^2 = [B]9[/B] [MEDIA=youtube]u_238Z7Mqk[/MEDIA]

A super deadly strain of bacteria is causing the zombie population to double every day. Currently, there are 25 zombies. After how many days will there be over 25,000 zombies? We set up our exponential function where n is the number of days after today: Z(n) = 25 * 2^n We want to know n where Z(n) = 25,000. 25 * 2^n = 25,000 Divide each side of the equation by 25, to isolate 2^n: 25 * 2^n / 25 = 25,000 / 25 The 25's cancel on the left side, so we have: 2^n = 1,000 Take the natural log of each side to isolate n: Ln(2^n) = Ln(1000) There exists a logarithmic identity which states: Ln(a^n) = n * Ln(a). In this case, a = 2, so we have: n * Ln(2) = Ln(1,000) 0.69315n = 6.9077 [URL='https://www.mathcelebrity.com/1unk.php?num=0.69315n%3D6.9077&pl=Solve']Type this equation into our search engine[/URL], we get: [B]n = 9.9657 days ~ 10 days[/B]

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cscx-cotx*cosx=sinx A few transformations we can make based on trig identities: [LIST] [*]csc(x) = 1/sin(x) [*]cot(x) = cos(x)/sin(x) [/LIST] So we have: 1/sin(x) - cos(x)/sin(x) * cos(x) = sin(x) (1 - cos^2(x))/sin(x) = sin(x) 1 - cos^2(x) = sin^2(x) This is [B]true[/B] from the identity: sin^2(x) - cos^2(x) = 1

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Express cos4? and sin4? in terms of sines and cosines of multiples of ?. Using a trignometric identity: cos (2?) = cos^2(?) - sin^2(?) Since 4? = 2*2?, so we have: [B]cos(4?) = cos^2(2?) - sin^2(2?)[/B] Using another trignometric identity, we have: sin(2?) = 2 sin(?) cos(?) Since 4? = 2*2?, so we have: [B]sin(4?) = 2 sin(2?) cos(2?)[/B]

How can you rewrite the number 1 as 2 to a power? There exists an identity which says, n^0 = 1 where n is a number. So [B]2^0 = 1[/B]

if Logb(5)=3.56 and logb(8)=4.61 then what is logb(40) There exists a logarithmic identity which says log(xy) = log(x) + log(y). Since the two logs above have the same base b, we have: x = 5 and y = 8. So we have: logb(40) = logb(5) + logb(8) logb(40) = 3.56 + 4.61 logb(40) = [B]8.17[/B]

log5 = 0.699, log2 = 0.301. Use these values to evaluate log40. One of the logarithmic identities is: log(ab) = log(a) + log(b). Using the numbers 2 and 5, we somehow need to get to 40. [URL='http://www.mathcelebrity.com/factoriz.php?num=40&pl=Show+Factorization']List factors of 40[/URL]. On the link above, take a look at the bottom where it says prime factorization. We have: 40 = 2 x 2 x 2 x 5 Using our logarithmic identity, we have: log40 = log(2 x 2 x 2 x 5) Rewriting this using our identity, we have: log40 = log2 + log2 + log2 + log5 log40 = 0.301 + 0.301 + 0.301 + 0.699 log40 = [B]1.602 [MEDIA=youtube]qyG_Jkf9VDc[/MEDIA][/B]

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Oliver invests $1,000 at a fixed rate of 7% compounded monthly, when will his account reach $10,000? 7% monthly is: 0.07/12 = .00583 So we have: 1000(1 + .00583)^m = 10000 divide each side by 1000; (1.00583)^m = 10 Take the natural log of both sides; LN (1.00583)^m = LN(10) Use the identity for natural logs and exponents: m * LN (1.00583) = 2.30258509299 0.00252458479m = 2.30258509299 m = 912.064867899 Round up to [B]913 months[/B]