1 integer is 7 times another. If the product of the 2 integers is 448, then find the integers.

1 integer is 7 times another. If the product of the 2 integers is 448, then find the integers.

Let the first integer be x and the second integer be y. We have the following two equations:

1. x = 7y
2. xy = 448

Substitute (1) into (2), we have:
(7y)y = 448
7y^2 = 448

Divide each side by 7
y^2 = 64
y = -8, 8

We use 8, since 8*7 = 56, and 56*8 =448. So the answer is (x, y) = (8, 56)