An ordinary fair die is rolled twice. The face value of the rolls is added together. Compute the pro

Discussion in 'Calculator Requests' started by math_celebrity, Sep 14, 2017.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    An ordinary fair die is rolled twice. The face value of the rolls is added together. Compute the probability of the following events: Event A: The sum is greater than 6. Event B: The sum is divisible by 5 or 6 or both.

    Sum greater than 6 = 7/12

    Sum is divisible by 5 or 6 or both
    This means a sum of 5, a sum of 6, a sum of 10, or a sum of 12.
    Sum of 5 = 1/9 or 4/36
    Sum of 6 = 5/36
    Sum of 10 = 1/12 or 3/36
    Sum of 12 = 1/36

    Adding all these up, we get:
    (4 + 5 + 3 + 1)/36
    13/36
     

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