A jet left Nairobi and flew east at an average speed of 231 mph. A passenger plane left four hours l

Discussion in 'Calculator Requests' started by math_celebrity, Sep 7, 2018.

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  1. math_celebrity

    math_celebrity Administrator Staff Member

    A jet left Nairobi and flew east at an average speed of 231 mph. A passenger plane left four hours later and flew in the same direction but with an average speed of 385 mph. How long did the jet fly before the passenger plane caught up?

    Jet distance = 231t
    Passenger plane distance = 385(t - 4)

    385(t - 4) = 231t
    385t - 1540 = 231t

    Subtract 231t from each side
    154t = 1540

    Type 154t = 1540 into the search engine, we get t = 10.

    Check our work:
    Jet distance = 231(10) = 2,310
    Passenger plane distance = 385(10 - 4) = 385 * 6 = 2,310
     

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