A rectangular field is to be enclosed with 1120 feet of fencing. If the length of the field is 40 fe

Discussion in 'Calculator Requests' started by math_celebrity, Jun 12, 2019.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A rectangular field is to be enclosed with 1120 feet of fencing. If the length of the field is 40 feet longer than the width, then how wide is the field?

    We're given:
    1. l = w + 40
    And we know the perimeter of a rectangle is:
    P = 2l + 2w

    Substitute (1) into this formula as well as the given perimeter of 1120:
    2(w + 40) + 2w = 1120

    Multiply through and simplify:
    2w + 80 + 2w = 1120

    Group like terms:
    4w + 80 = 1120

    Typing this equation into our search engine, we get:
    w = 260
     

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