If 3x - y = 12, what is the value of 8^x/2^y

If 3x - y = 12, what is the value of 8^x/2^y

We know 8 = 2^3

So using a rule of exponents, we have:
(2^3)^x/2^y
2^(3x)/2^y

Using another rule of exponents, we rewrite this fraction as:
2^(3x -y)

We're given 3x - y = 12, so we have:
2^12