2 consecutive even integers that equal 118

Let x be the first even integer. That means the next consecutive even integer must be x + 2.

Set up our equation:
x + (x + 2) = 118

Group x terms
2x + 2 = 118

Subtract 2 from each side
2x = 116

Divide each side by 2
x = 58

Which means the next consecutive even integer is 58 + 2 = 60
So our two consecutive even integers are 58, 60

Check our work:
58 + 60 = 118