Find two consecutive positive integers such that the difference of their square is 25

Find two consecutive positive integers such that the difference of their square is 25.

Let the first integer be n. This means the next integer is (n + 1).

Square n: n^2
Square the next consecutive integer: (n + 1)^2 = n^2 + 2n + 1

Now, we take the difference of their squares and set it equal to 25:
(n^2 + 2n + 1) - n^2 = 25

Cancelling the n^2, we get:
2n + 1 = 25

Typing this equation into our search engine, we get:
n = 12