The distance between consecutive bases is 90 feet. An outfielder catches the ball on the third base

Discussion in 'Calculator Requests' started by math_celebrity, Mar 1, 2020.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    The distance between consecutive bases is 90 feet. An outfielder catches the ball on the third base line about 40 feet behind third base. How far would the outfielder have to throw the ball to first base?

    We have a right triangle. From home base to third base is 90 feet. We add another 40 feet to the outfielder behind third base to get: 90 + 40 = 130

    The distance from home to first is 90 feet.

    Our hypotenuse is the distance from the outfielder to first base.

    Using our Pythagorean theorem calculator, we get:
    d = 158.11 feet
     

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