The only way you can roll a 12 with two dice is 6 and 6. Since each die roll is independent, we have: P(12) = P(6) * P(6) P(12) = 1/6 * 1/6 P(12) = 1/36. Now, what is the probability we roll a 12 five times in a row? The same rules apply, each new roll is independent of the last, so we multiply: P(12, 12, 12, 12, 12) = 1/36 * 1/36 * 1/36 * 1/36 * /36 P(12, 12, 12, 12, 12) = 1/60,466,176 or 1.65381717e-8