Given: BC = EF AC = EG AB = 10 BC = 3 Prove FG = 10

Discussion in 'Calculator Requests' started by math_celebrity, Oct 2, 2020.

Tags:
  1. math_celebrity

    math_celebrity Administrator Staff Member

    Given: BC = EF

    AC = EG

    AB = 10

    BC = 3

    Prove FG = 10

    • AC = AB + BC (Segment Addition Postulate)
    • AB = 10, BC = 3 (Given)
    • AC = 10 + 3 (Substitution Property of Equality)
    • AC = 13 (Simplify)
    • AC = EG, BC = EF (Given)
    • EG = 13, EF = 3 (Segment Equivalence)
    • EG = EF + FG (Segment Addition Postulate)
    • 13 = 3 + FG (Substitution Property of Equality)
    • FG = 10 (Subtraction Property)
     
    math_celebrity, Oct 2, 2020
    #1

Share This Page