9 friends brought 178 tickets How many more ticket would they have to buy for all of them could have

Discussion in 'Calculator Requests' started by math_celebrity, Nov 30, 2020.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    9 friends brought 178 tickets How many more ticket would they have to buy for all of them could have the same amount?

    If we take 178 mod 9 to find the remainder, we get 7.

    If we buy the 7 more (remainder) tickets, we have:
    9 friends - 7 remainder = 2 tickets

    To prove our work, we add the 2 tickets + 178 tickets = 180 tickets
    180 tickets / 9 friends = 20 tickets per friends

    So our answer is 2 tickets
     

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