A company’s number of personnel on active duty (not on sick leave or vacation leave) during the peri

Discussion in 'Calculator Requests' started by math_celebrity, Sep 27, 2021.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A company’s number of personnel on active duty (not on sick leave or vacation leave) during the period 2000 - 2013 can be approximated by the cubic model f(x) = 2.5x^3 - 15x^2 - 80x + 1025, where x = 0 corresponds to 2000. Based on the model, how many personnel were on active duty in 2010? What is the domain of f?

    If x = 0 corresponds to 2000, when 2010 is 2010 - 2000 = 10. We want f(10):
    f(10) = 2.5(10)^3 - 15(10)^2 - 80(10) + 1025
    f(10) = 2.5(1000) - 15(100) - 800 + 1025
    f(10) = 2500 - 1500 - 800 + 1025
    f(10) = 1,225
     

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