An eccentric millionaire decided to give away $1,000,000 if Janelle took one die and rolled a "4". H

Discussion in 'Calculator Requests' started by math_celebrity, Dec 3, 2022.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    An eccentric millionaire decided to give away $1,000,000 if Janelle took one die and rolled a "4". He wanted Janelle to have a better than 1 in 6 chance of winning, so before she rolled the die he told her that she could roll the die 3 times. If any roll was a "4", she would win the million dollars. What are Janelle's chances of winning the million dollars?

    Chance of winning each roll is 1/6. Which means the chances of losing each roll are 1 - 1/6 = 5/6

    Calculate the probability of 3 straight losing rolls:
    P(Lose) = P(Loser) * P(Loser) * P(Loser) = 5/6 * 5/6 * 5/6 = 125/216
    P(Win) = 1 - P(Lose)
    P(Win) = 1 - 125/216
    P(Win) = 216/216 -125/216
    P(Win) = 91/216
     

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