A 6000 seat theater has tickets for sale at $24 and $40. How many tickets should be sold at each pri

Discussion in 'Calculator Requests' started by math_celebrity, Dec 3, 2016.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A 6000 seat theater has tickets for sale at $24 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $188,800?

    Let x be the number of $24 tickets, and y be the number of $40 tickets. We have:
    1. 24x + 40y = 188,800
    2. x + y = 6,000
    3. Rearrange (2) to solve for x: x = 6000 - y
    4. Plug in (3) to (1):
    24(6000 - y) + 40y = 188800
    144,000 - 24y + 40y = 188,800
    16y + 144,000 = 188,800

    Subtract 144,000 from each side:
    16y = 44,800

    Divide each side by 16
    y = 2,800 ($40 tickets)

    Plug this into (2)
    x + 2,800 = 6000

    Subtract 2,800 from each side:
    x = 3,200 ($24 tickets)
     

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