A passenger train left station A at 6:00 P.M. Moving with the average speed 45 mph, it arrived at st

Discussion in 'Calculator Requests' started by math_celebrity, Jan 29, 2017.

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  1. math_celebrity

    math_celebrity Administrator Staff Member

    A passenger train left station A at 6:00 P.M. Moving with the average speed 45 mph, it arrived at station B at 10:00 p.m. A transit train left from station A 1 hour later than the passenger train, but it arrived at the station B at the same time with the passenger train. What was the average speed of the transit train?

    Passenger Train
    • 45 miles per hour and it got there in 4 hours.
    Using our formula D = rt where:
    • D = Distance
    • r = rate
    • t = time
    • D = rt
    • D = 45(4)
    • D = 180 miles from Station A to Station B
    Transit Train
    • It has to go the same distance, 180 miles, so D = 180
    • It made it there in 3 hours. This is r
    • We want to solve for t
    D = rt
    180 = 3r

    Divide each side by 3
    r = 60 miles per hour
     

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