A boy is 10 years older than his brother. In 4 years he will be twice as old as his brother. Find th

Discussion in 'Calculator Requests' started by math_celebrity, Jan 26, 2020.

  1. math_celebrity

    math_celebrity Administrator Staff Member

    A boy is 10 years older than his brother. In 4 years he will be twice as old as his brother. Find the present age of each?

    Let the boy's age be b and his brother's age be c. We're given two equations:

    1. b = c + 10
    2. b + 4 = 2(c + 4)
    Substitute equation (1) into equation (2):
    (c + 10) + 4 = 2(c + 4)

    Simplify by multiplying the right side through and grouping like terms:
    c + 14 = 2c + 8

    Type this equation into our search engine and we get:
    c = 6

    Now plug c = 6 into equation (1):
    b = 6 + 10
    b = 16
     

Share This Page