Given: BC = EF AC = EG AB = 10 BC = 3 Prove FG = 10 AC = AB + BC (Segment Addition Postulate) AB = 10, BC = 3 (Given) AC = 10 + 3 (Substitution Property of Equality) AC = 13 (Simplify) AC = EG, BC = EF (Given) EG = 13, EF = 3 (Segment Equivalence) EG = EF + FG (Segment Addition Postulate) 13 = 3 + FG (Substitution Property of Equality) FG = 10 (Subtraction Property)