Melissa runs a landscaping business. She has equipment and fuel expenses of $264 per month. If she c

Discussion in 'Calculator Requests' started by math_celebrity, Sep 4, 2017.

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  1. math_celebrity

    math_celebrity Administrator Staff Member

    Melissa runs a landscaping business. She has equipment and fuel expenses of $264 per month. If she charges $53 for each lawn, how many lawns must she service to make a profit of at $800 a month?

    Melissa has a fixed cost of $264 per month in fuel. No variable cost is given. Our cost function is:
    C(x) = Fixed Cost + Variable Cost. With variable cost of 0, we have:
    C(x) = 264

    The revenue per lawn is 53. So R(x) = 53x where x is the number of lawns.

    Now, profit is Revenue - Cost. Our profit function is:
    P(x) = 53x - 264

    To make a profit of $800 per month, we set P(x) = 800.
    53x - 264 = 800

    Using our equation solver, we get:
    x ~ 21 lawns
     

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