The sum of 3 consecutive odd numbers equals 117. What are the 3 odd numbers?

1) Set up an equation where our

*odd numbers*are n, n + 2, n + 4

2) We increment by 2 for each number since we have

*odd numbers*.

3) We set this sum of consecutive

*odd numbers*equal to 117

n + (n + 2) + (n + 4) = 117

**Simplify this equation by grouping variables and constants together:**

(n + n + n) + 2 + 4 = 117

3n + 6 = 117

**Subtract 6 from each side to isolate 3n:**

3n + 6 - 6 = 117 - 6

**Cancel the 6 on the left side and we get:**

3n +

3n = 111

**Divide each side of the equation by 3 to isolate n:**

3n/3 = 111/3

**Cancel the 3 on the left side:**

n = 37

Call this n1, so we find our other 2 numbers

n2 = n1 + 2

n2 = 37 + 2

n2 = 39

n3 = n2 + 2

n3 = 39 + 2

n3 = 41

**List out the 3 consecutive odd numbers**

(

**37, 39, 41**)

37 ← 1st number, or the Smallest, Minimum, Least Value

39 ← 2nd number

41 ← 3rd or the Largest, Maximum, Highest Value