sum of 3 consecutive odd integers equals 1 hundred 17 The sum of 3 consecutive odd numbers equals 117. What are the 3 odd numbers? 1) Set up an equation where our odd numbers are n, n + 2, n + 4 2) We increment by 2 for each number since we have odd numbers. 3) We set this sum of consecutive odd numbers equal to 117 n + (n + 2) + (n + 4) = 117 Simplify this equation by grouping variables and constants together: (n + n + n) + 2 + 4 = 117 3n + 6 = 117 Subtract 6 from each side to isolate 3n: 3n + 6 - 6 = 117 - 6 Cancel the 6 on the left side and we get: 3n + 6 - 6 = 117 - 6 3n = 111 Divide each side of the equation by 3 to isolate n: 3n/3 = 111/3 Cancel the 3 on the left side: 3n/3 = 111/3 n = 37 Call this n1, so we find our other 2 numbers n2 = n1 + 2 n2 = 37 + 2 n2 = 39 n3 = n2 + 2 n3 = 39 + 2 n3 = 41 List out the 3 consecutive odd numbers (37, 39, 41) 37 ← 1st number, or the Smallest, Minimum, Least Value 39 ← 2nd number 41 ← 3rd or the Largest, Maximum, Highest Value