# The total age of three cousins is 48. Suresh is half as old as Hakima and 4 years older than Saad. h

Discussion in 'Calculator Requests' started by math_celebrity, Jun 23, 2019.

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1. ### math_celebrityAdministratorStaff Member

The total age of three cousins is 48. Suresh is half as old as Hakima and 4 years older than Saad. How old are the cousins?

Let a be Suresh's age, h be Hakima's age, and c be Saad's age. We're given:
1. a + h + c = 48
2. a = 0.5h
3. a = c + 4
To isolate equations in terms of Suresh's age (a), let's do the following:
• Rewriting (3) by subtracting 4 from each side, we get c = a - 4
• Rewriting (2) by multiply each side by 2, we have h = 2a
We have a new system of equations:
1. a + h + c = 48
2. h = 2a
3. c = a - 4
Plug (2) and (3) into (1)
a + (2a) + (a - 4) = 48

Group like terms:
(1 + 2 + 1)a - 4 = 48
4a - 4 = 48

Typing this equation into our search engine, we get:
a = 13 <-- Suresh's age

This means that Hakima's age, from modified equation (2) above is:
h = 2(13)
h = 26 <-- Hakima's age

This means that Saad's age, from modified equation (3) above is:
c = 13 - 4
c = 9 <-- Saad's age