We want P(X = Even) or P(X>6)

With 2 dice, our die totals are:

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

Evens are: 2, 4, 6, 8, 10, 12

> 6 = 7, 8, 9, 10, 11, 12

When the problem states

*or*it means either of the sets. When we take the union of both sets, we get:

2,4,6,7,8,9,10,11,12

This is 9 possible entries out of 12:

9/12

We can simplify this by dividing top and bottom by 3:

P(X = Even) or P(X>6) =

**3/4 or 0.75**