Enter function
With the function that you entered of 2x - 5, plot points, determine the intercepts, domain, range

Since you did not specify a qualifying variable or function notation in your expression, we will assume y
y = 2x - 5

Determine function type:

Since we have a variable with no exponents:
this is a linear function

Since this is a linear function
it is a direct variation equation. The constant of proportionality is 2

Now Plot points from 10 to -10

xPlug in xƒ(x) = 2x - 5Ordered Pair
-102(-10)-5-25(-10, -25)
-92(-9)-5-23(-9, -23)
-82(-8)-5-21(-8, -21)
-72(-7)-5-19(-7, -19)
-62(-6)-5-17(-6, -17)
-52(-5)-5-15(-5, -15)
-42(-4)-5-13(-4, -13)
-32(-3)-5-11(-3, -11)
-22(-2)-5-9(-2, -9)
-12(-1)-5-7(-1, -7)
02(0)-5-5(0, -5)
12(1)-5-3(1, -3)
22(2)-5-1(2, -1)
32(3)-51(3, 1)
42(4)-53(4, 3)
52(5)-55(5, 5)
62(6)-57(6, 7)
72(7)-59(7, 9)
82(8)-511(8, 11)
92(9)-513(9, 13)
102(10)-515(10, 15)

Determine the y-intercept:

The y-intercept is found when x is set to 0. From the grid above, our y-intercept is -5

Determine the x-intercept

The x-intercept is found when y is set to 0
The y-intercept is found when y is set to 0. From the grid above, our x-intercept is 0

Determine the domain of the function:

The domain represents all values of x that you can enter
The domain is (-∞, ∞) or All Real Numbers

Determine the range of the function:

The range is all the possible values of y or ƒ(x) that can exist
The range is (-∞, ∞) or All Real Numbers


(-10, -25)
(-9, -23)
(-8, -21)
(-7, -19)
(-6, -17)
(-5, -15)
(-4, -13)
(-3, -11)
(-2, -9)
(-1, -7)
(0, -5)
(1, -3)
(2, -1)
(3, 1)
(4, 3)
(5, 5)
(6, 7)
(7, 9)
(8, 11)
(9, 13)
(10, 15)