Answer
xn = 11.782058881732
↓Steps Explained:↓
The half-life of a substance is 15.
At time = 0, this substance has size 45
Calculate the size of the substance at time = 29.
Step 1: Calculate Time Difference (Δ)
Δ = tn - t
Δ = 29. - 0
Δ = 29
Step 2: Calculate number of half-lives (hn)
| hn = | Δ |
| h |
| hn = | 29 |
| 15. |
hn = 1.9333333333333 <-- Number of times we will reduce our original size by ½
Step 3: Calculate New Substance Size (xn)
We go through each time starting at t = 0 all the way to hn = 1.9333333333333
Substance size at time = 1
x1 = ½(x0)
x1 = ½(45)
x1 = 22.5
Shortcut Solution to Above
xn = ½hnx0
xn = ½1.9333333333333(45)
| xn = | 45 |
| 3.8193664156417 |
xn = 11.782058881732
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