The half-life of a substance is 12.
At time = 0, this substance has size 60
Calculate the size of the substance at time = 33.
Δ = tn - t
Δ = 33. - 0
Δ = 33
hn = | Δ |
h |
hn = | 33 |
12. |
hn = 2.75 <-- Number of times we will reduce our original size by ½
We go through each time starting at t = 0 all the way to hn = 2.75
x1 = ½(x0)
x1 = ½(60)
x1 = 30
x2 = ½(x1)
x2 = ½(30)
x2 = 15
xn = ½hnx0
xn = ½2.75(60)
xn = | 60 |
6.7271713220297 |