Initial Size of at time =
<-- Half-Life
<-- Evaluate at time tn
  

The half-life of a substance is 12.

At time = 0, this substance has size 60

Calculate the size of the substance at time = 33.

Step 1: Calculate Time Difference (Δ)

Δ = tn - t

Δ = 33. - 0

Δ = 33

Step 2: Calculate number of half-lives (hn)

hn  =  Δ
  h

hn  =  33
  12.

hn = 2.75  <-- Number of times we will reduce our original size by ½

Step 3: Calculate New Substance Size (xn)

We go through each time starting at t = 0 all the way to hn = 2.75

Substance size at time = 1

x1 = ½(x0)

x1 = ½(60)

x1 = 30

Substance size at time = 2

x2 = ½(x1)

x2 = ½(30)

x2 = 15

Shortcut Solution to Above

xn = ½hnx0

xn = ½2.75(60)

xn  =  60
  6.7271713220297


xn = 8.9190533625204