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Hexagon has perimeter (P) of of 9

calculate the side length (s) and Area (A)

The perimeter for a hexagon (P) is given below:

P = 6 x s

Dividing each side by 6, we get:

P
6
=
  
6s
6

Cancel the 6, we get:

s  =  P
  6

Plugging in our perimeter value of 9, we get:

s  =  9
  6

s = 1.5

A  =  3√3s2
  2

A  =  3√3(1.52)
  2

A  =  3√3(2.25)
  2

A  =  11.69134295109
  2

Calculate Area (A):

A  =  3√3s2
  2

A  =  3√3(1.52)
  2

A  =  3√3(2.25)
  2

A  =  11.69134295109
  2

A = 5.845671475545

Calculate Sum of the Interior Angles:

Interior Angle Sum = (sides - 2) x 180°

Interior Angle Sum = (6 - 2) x 180°

Interior Angle Sum = 4 x 180°

Interior Angle sum = 720°

Calculate polygon diagonals

Diagonals  =  n(n - 3)
  2

Diagonals  =  6(6 - 3)
  2

Diagonals  =  6(3)
  2

Diagonals  =  18
  2

Diagonals = 9

Calculate 1 vertex diagonals:

1 vertex Diagonals = n - 3

1 vertex Diagonals = 6 - 3

1 vertex Diagonals = 3

Calculate triangles from one vertex:

Triangles = N - 2

Triangles = 6 - 2

Triangles = 4

Other Properties:

Sides (Edges) = 6

Faces = 1

Vertices = 6

Final Answers


P = 9
s = 1.5
A = 5.845671475545
Interior Angle sum = 720°
Diagonals = 9
1 vertex Diagonals = 3
Triangles = 4
Sides (Edges) = 6
Faces = 1
Vertices = 6