Evaluate the vertical parabola
(y-2)2 = 12(x-5)
Since our squared variable is y, our parabola has a horizontal opening.
Our standard for for this parabola is (y - k)2 = 4c(x - h)
Therefore, our vertex (h,k) = (5,2)
From the right side of our standard form equation, we have 4c = 12
4c | |
4 |
= |
12 |
4 |
c = 3
The focus for a horizontal parabola is (h + c,k)
Substituting our values into this equation, we get:
Focus = (5 + 3,2)
Focus = (8,2)
The directrix equation for a horizontal parabola is x = c
Therefore, for c = 3, we have x = 3