Evaluate the combination:
9C3
A unique order or arrangement
nCr = | n! |
r!(n - r)! |
where n is the number of items
r is the unique arrangements.
9C3 2 | 9! |
3!(9 - 3)! |
n! = n * (n - 1) * (n - 2) * .... * 2 * 1
n! = 9!
9! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
9! = 362,880
(n - r)! = (9 - 3)!
(9 - 3)! = 6!
6! = 6 x 5 x 4 x 3 x 2 x 1
6! = 720
r! = 3!
3! = 3 x 2 x 1
3! = 6
9C3 = | 362,880 |
6 x 720 |
9C3 = | 362,880 |
4,320 |