Enter square root or exponent statement:

Evaluate the following

-58

Term 1 has a square root, so we evaluate and simplify:

A negative square root needs to use imaginary numbers:

The imaginary number i is denoted as √-1

Simplify √-58.

Since -58 is less than 0, we have an imaginary number of i where i = √-1
We can express this as √58-1
Since √-1 = i, we have √58i

Simplify √58.

Checking square roots, we see that

72 = 49 and 82 = 64

Our answer in decimal format is between 7 and 8

Our answer is not an integer

Simplify it into the product of an integer and a radical.

We do this by listing each product combo of 58

Check for integer square root values below:

58 = √158

58 = √229

From that list, the highest factor with an integer square root is 1

Therefore, we use the product combo √58 = √158

Evaluating square roots, we see that √1 = 1

Since 1 is the greatest common factor, this square root cannot be simplified any further:

Multiply by our constant of 1

58i = ±sqrt(58)i

From that list, the highest factor with an integer square root is 1

Therefore, we use the product combo √-58 = √1-58

Evaluating square roots, we see that √1 = 1

Since 1 is the greatest common factor, this square root cannot be simplified any further:

Multiply by our constant of 1

Group square root terms for 1

1√-58


Final Answer:


1√-58