Since -58 is less than 0, we have an imaginary number of i where i = √-1
We can express this as √58√-1
Since √-1 = i, we have √58i
√58i = ±sqrt(58)i

Answer

↓Steps Explained:↓

Evaluate the following

√-58

Term 1 has a square root, so we evaluate and simplify:

Group square root terms for 1

1√-58

Final Answer:

1√-58

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