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A rectangle has length x width of 4 x 3
Calculate the perimeter and area
A = l x w
where l = length and w = width
Plug in l = 4 and w = 3
A = 4 x 3
A = 12
P = 2(l + w)
where l = length and w = width
Plug in l = 4 and w = 3
P = 2 * (4 + 3)
P = 2 * 7
P = 14
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 4 and w = 3
Diagonal = √42 + 32
Diagonal = √16 + 9
Diagonal = √25
Diagonal = 5
R = | √l2 + w2 |
2 |
R = | √42 + 32 |
2 |
R = | √16 + 9 |
2 |
R = | √25 |
2 |
R = | 5 |
2 |
R = 2.5
r = | 12 |
7 |
r = | lw |
l + w |
r = | (4)(3) |
4 + 3 |
r = | 12 |
7 |
r = 1.7142857142857
Faces = 1
Edges = 4
Vertices = 4