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A rectangle has length x width of 5 x 4
Calculate the perimeter and area
A = l x w
where l = length and w = width
Plug in l = 5 and w = 4
A = 5 x 4
A = 20
P = 2(l + w)
where l = length and w = width
Plug in l = 5 and w = 4
P = 2 * (5 + 4)
P = 2 * 9
P = 18
Diagonal = √l2 + w2
where l = length and w = width
Plug in l = 5 and w = 4
Diagonal = √52 + 42
Diagonal = √25 + 16
Diagonal = √41
Diagonal = 6.4031242374328
R = | √l2 + w2 |
2 |
R = | √52 + 42 |
2 |
R = | √25 + 16 |
2 |
R = | √41 |
2 |
R = | 6.4031242374328 |
2 |
R = 3.2015621187164
r = | 20 |
9 |
r = | lw |
l + w |
r = | (5)(4) |
5 + 4 |
r = | 20 |
9 |
r = 2.2222222222222
Faces = 1
Edges = 4
Vertices = 4