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Using the Rule of 72...
How long for money to double at 6%?
(1 + i)n = 2
1 unit of money doubles in
n periods at interest rate i is:
(1 + i)n = 2
Ln(1 + i)n = Ln(2)
Ln(an) = n * Ln(a)
Using that identity, we have a = (1 + i):
n * Ln(1 + i) = Ln(2)
n = | Ln(2) |
Ln(1 + i) |
n = | 0.6931 |
Ln(1 + i) |
n = | 0.6931 * i |
Ln(1 + i) * i |
n = | 0.6931 * 0.06 |
0.06 * Ln(1 + 0.06) |
n = | 0.6931 * 0.06 |
0.06 * Ln(1.06) |
n = | 0.6931 * 0.06 |
i * 0.058268908123976 |
n = | 0.6931 * 1.0297086719446 |
i |
n~ = | 0.72 |
i |
n~ = | 0.72 |
0.06 |