variation
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A direct variation includes the points ( – 5, – 20) and (n,8). Find n.A direct variation includes the points ( – 5, – 20) and (n,8). Find n.
Slopes are proportional for rise over run. Set up a proportion of x's to y's:
-5/n = -20/8
To solve this proportion for n, we [URL='https://www.mathcelebrity.com/prop.php?num1=-5&num2=-20&den1=n&den2=8&propsign=%3D&pl=Calculate+missing+proportion+value']type it in our math engine[/URL] and we get:
n = [B]2[/B]
a varies directly with b and inversely with ca varies directly with b and inversely with c
Direct variation means we multiply.
Inverse variation means we divide.
There exists a constant k such that:
[B]a = kb/c[/B]
b varies directly as a. if b is 78 when a is 13, what is b when a is 23?b varies directly as a. if b is 78 when a is 13, what is b when a is 23?
[URL='https://www.mathcelebrity.com/variation.php?var1=b&cmeth=varies+directly+as&var2=a&init1=b%3D78&init2=a%3D13&g1=a%3D23&pl=Calculate+Variation']Using our direct variation calculator[/URL], we get:
b = [B]138[/B]
b varies directly as the sum of x and yb varies directly as the sum of x and y
This is a direct variation problem.
Direct variation means there exists a constant k such that:
[B]b = k(x + y)[/B]
C varies directly as d use k as the constant of variationC varies directly as d use k as the constant of variation
Direct variation means we multiply below:
[B]C = kd[/B]
C varies directly as the cube of a and inversely as the 4th power of BC varies directly as the cube of a and inversely as the 4th power of B
The cube of a means we raise a to the 3rd power:
a^3
The 4th power of B means we raise b to the 4th power:
b^4
Varies directly means there exists a constant k such that:
C = ka^3
Also, varies inversely means we divide by the 4th power of B
C = [B]ka^3/b^4[/B]
Varies [I]directly [/I]as means we multiply by the constant k.
Varies [I]inversely [/I]means we divide k by the term which has inverse variation.
[MEDIA=youtube]fSsG1OB3qdk[/MEDIA]
does the equation y= x/3 represent a direct variation? If so, state the value of kdoes the equation y= x/3 represent a direct variation? If so, state the value of k
[B]Yes[/B], it's a direct variation equation. We rewrite this as:
y = 1/3 * x
So k = 1/3, and y varies directly as x.
F varies directly as g and inversely as r^2F varies directly as g and inversely as r^2
[U]Givens and assumptions[/U]
[LIST]
[*]We take a constant of variation called k.
[*][I]Varies directly means we multiply our variable term by k[/I]
[*][I]Varies inversely means we divide k by our variable term[/I]
[/LIST]
The phrase varies directly or varies inversely means we have a constant k such that:
[B]F = kg/r^2[/B]
f varies jointly with u and h and inversely with the square of y.f varies jointly with u and h and inversely with the square of y.
Variation means we have a constant k.
Varies jointly with u and h means we multiply k by hu
Varies inversely with the square of y means we divide by y^2
[B]f = khu/y^2[/B]
Given y= 4/3x what is the constant of proportionalityGiven y= 4/3x what is the constant of proportionality
Direct variation means the constant of proportionality is y/x.
Cross multiplying, we get:
y/x = [B]4/3[/B]
If 100 runners went with 4 bicyclists and 5 walkers, how many bicyclists would go with 20 runners anIf 100 runners went with 4 bicyclists and 5 walkers, how many bicyclists would go with 20 runners and 2 walkers?
[U]Set up a joint variation equation, for the 100 runners, 4 bicyclists, and 5 walkers:[/U]
100 = 4 * 5 * k
100 = 20k
[U]Divide each side by 20[/U]
k = 5 <-- Coefficient of Variation
[U]Now, take scenario 2 to determine the bicyclists with 20 runners and 2 walkers[/U]
20 = 2 * 5 * b
20 = 10b
[U]Divide each side by 10[/U]
[B]b = 2[/B]
If p is inversely proportional to the square of q, and p is 2 when q is 4, determine p when q is equIf p is inversely proportional to the square of q, and p is 2 when q is 4, determine p when q is equal to 2.
We set up the variation equation with a constant k such that:
p = k/q^2 [I](inversely proportional means we divide)
[/I]
When q is 4 and p is 2, we have:
2 = k/4^2
2 = k/16
Cross multiply:
k = 2 * 16
k = 32
Now, the problem asks for p when q = 2:
p = 32/2^2
p = 32/4
p = [B]8
[MEDIA=youtube]Mro0j-LxUGE[/MEDIA][/B]
If x varies directly with y and x = -3 when y = 12, what is the constant of variation?If x varies directly with y and x = -3 when y = 12, what is the constant of variation?
Using our [URL='https://www.mathcelebrity.com/community/forums/calculator-requests.7/create-thread']variation calculator[/URL], we see the constant of variation (k) is:
k =[B] -1/4 or -0.25[/B]
If y varies inversely as X and Y equals 5 when x equals 2 find X when Y is 4If y varies inversely as X and Y equals 5 when x equals 2 find X when Y is 4.
Using our [URL='http://www.mathcelebrity.com/variation.php?var1=y&cmeth=varies+inversely+as&var2=x&init1=y%3D5&init2=x%3D2&g1=y%3D4&pl=Calculate+Variation']inverse variation calculator[/URL], we get x = 2.5
If y=-72 when x=6, find y when x is 3If y=-72 when x=6, find y when x is 3
Using our [URL='https://www.mathcelebrity.com/variation.php?var1=y&cmeth=varies+directly+as&var2=x&init1=y%3D-72&init2=x%3D6&g1=x%3D3&pl=Calculate+Variation']variation calculator[/URL], we get
y = [B]-36[/B]
Joint Variation EquationsFree Joint Variation Equations Calculator - Given a joint variation (jointly proportional) of a variable between two other variables with a predefined set of conditions, this will create the joint variation equation and solve based on conditions.
Also called combined variation.
P varies directly as q and the square of r and inversely as sP varies directly as q and the square of r and inversely as s
There exists a constant k such that:
p = kqr^2/s
[I]Note: Direct variations multiply and inverse variations divide[/I]
p varies directly as the square of r and inversely as q and s and p = 40 when q = 5, r = 4 and s = 6p varies directly as the square of r and inversely as q and s and p = 40 when q = 5, r = 4 and s = 6, what is the equation of variation?
Two rules of variation:
[LIST=1]
[*]Varies directly means we multiply
[*]Varies inversely means we divide
[/LIST]
There exists a constant k such that our initial equation of variation is:
p = kr^2/qs
[B][/B]
With p = 40 when q = 5, r = 4 and s = 6, we have:
4^2k / 5 * 6 = 40
16k/30 = 40
Cross multiply:
16k = 40 * 30
16k = 1200
Using our [URL='https://www.mathcelebrity.com/1unk.php?num=16k%3D1200&pl=Solve']equation calculator[/URL], we get:
k = [B]75[/B]
So our final equation of variation is:
[B]p = 75r^2/qs[/B]
p= 4/q what kind of variation is this?p= 4/q what kind of variation is this?
[B]Inverse Variation [/B]since we divide by q
Sample Size Reliability for μFree Sample Size Reliability for μ Calculator - Given a population standard deviation σ, a reliability (confidence) value or percentage, and a variation, this will calculate the sample size necessary to make that test valid.
Sample Size Requirement for the Difference of MeansFree Sample Size Requirement for the Difference of Means Calculator - Given a population standard deviation 1 of σ1, a population standard deviation 2 of σ2 a reliability (confidence) value or percentage, and a variation, this will calculate the sample size necessary to make that test valid.
Suppose that h(x) varies directly with x and h(x)=44 when x = 2. What is h(x) when x = 1.5?Suppose that h(x) varies directly with x and h(x)=44 when x = 2. What is h(x) when x = 1.5?
Direct variation means we set up an equation:
h(x) = kx where k is the constant of variation.
For h(x) = 44 when x = 2, we have:
2k = 44
[URL='https://www.mathcelebrity.com/1unk.php?num=2k%3D44&pl=Solve']Type this equation into our search engine[/URL], we get:
k = 22
The question asks for h(x) when x = 1.5. So we set up our variation equation, knowing that k = 22.
kx = h(x)
With k = 22 and x = 1.5, we get:
22(1.5) = h(x)
h(x) = [B]33[/B]
Use k as the constant of variation. L varies jointly as u and the square root of v.Use k as the constant of variation. L varies jointly as u and the square root of v.
Since u and v vary jointly, we multiply by the constant of variation k:
[B]l = ku * sqrt(v)[/B]
Variation EquationsFree Variation Equations Calculator - This calculator solves the following direct variation equations and inverse variation equations below:
* y varies directly as x
* y varies inversely as x
* y varies directly as the square of x
* y varies directly as the cube of x
* y varies directly as the square root of x
* y varies inversely as the square of x
* y varies inversely as the cube of x
* y varies inversely as the square root of x
What can we conclude if the coefficient of determination is 0.94?What can we conclude if the coefficient of determination is 0.94?
[LIST]
[*]Strength of relationship is 0.94
[*]Direction of relationship is positive
[*]94% of total variation of one variable(y) is explained by variation in the other variable(x).
[*]All of the above are correct
[/LIST]
[B]94% of total variation of one variable(y) is explained by variation in the other variable(x)[/B]. The coefficient of determination explains ratio of explained variation to the total variation.
X varies directly with the cube root of y when x=1 y=27. Calculate y when x=4X varies directly with the cube root of y when x=1 y=27. Calculate y when x=4
Varies directly means there is a constant k such that:
x = ky^(1/3)
When x = 1 and y = 27, we have:
27^1/3(k) = 1
3k = 1
To solve for k, we[URL='https://www.mathcelebrity.com/1unk.php?num=3k%3D1&pl=Solve'] type in our equation into our search engine[/URL] and we get:
k = 1/3
Now, the problem asks for y when x = 4. We use our variation equation above with k = 1/3 and x = 4:
4 = y^(1/3)/3
Cross multiply:
y^(1/3) = 4 * 3
y^(1/3) =12
Cube each side:
y^(1/3)^3 = 12^3
y = [B]1728[/B]
y varies directly as x and inversely as iy varies directly as x and inversely as I
Note:
Direct variation means we multiply. Inverse variation means we divide.
There exists a constant k such that:
[B]y = kx/i[/B]
z varies directly with x and inversely with yz varies directly with x and inversely with y
[LIST]
[*]The phrase directly means we multiply.
[*]The phrase inversely means we divide
[*]Variation means there exists a constant k such that:
[/LIST]
[B]z = kx/y[/B]
z varies jointly as x and y. If z=3 when x=3 and y=15, find z when x=6 and y=9z varies jointly as x and y. If z=3 when x=3 and y=15, find z when x=6 and y=9
Varies jointly means there exists a constant k such that:
z = kxy
We're given z = 3 when x = 3 and y = 15, so we have:
3 = 15 * 3 * k
3 = 45k
Using our [URL='https://www.mathcelebrity.com/1unk.php?num=3%3D45k&pl=Solve']equation solver,[/URL] we see that:
k = 1/15
So our joint variation equation is:
z = xy/15
Then we're asked to find z when x = 6 and y = 9
z = 6 * 9 / 15
z = 54/15
[URL='https://www.mathcelebrity.com/search.php?q=54%2F15&x=0&y=0']z =[/URL] [B]18/5[/B]