Use Substitution to solve 1c + 2p = 12.40 and 2c + 3p = 20.20
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Use the substitution method to solve:
1c + 2p = 12.40
2c + 3p = 20.20
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
2c + 3p = 20.20
Subtract 3p from both sides to isolate c:
2c + 3p - 3p = 20.20 - 3p
2c = 20.20 - 3p
Now divide by 2:
2c
2
=
20.20 - 3p
2
Revised Equation 2:
c =
20.20 - 3p
2
Plug Revised Equation 2 value into c:
1(c) + 2p = 12.40
1 * ((20.20 - 3p)/2) + 2p = 12.40
((20.2 - 3p)/2) + 2p = 12.40
Multiply equation 1 through by 2
2 * (((20.2 - 3p)/2) + 2p = 12.40)
2 * (((20.2 - 3p)/2) + 2p = 12.40)
20.2 - 3p + 4p = 24.8
Group like terms:
-3p + 4p = 24.8 - 20.2
1p = 4.6
Divide each side by 1
1p
1
=
4.6
1
p =
4.6
1
p = 4.6
Plug this answer into Equation 1
1c + 2(4.6) = 12.40
1c + 9.2 = 12.40
1c = 12.40 - 9.2
1c = 3.2
Divide each side by 1
1c
1
=
3.2
1
c =
3.2
1
c = 3.2
What is the Answer?
c = 3.2 and p = 4.6
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
Pick any 3 of the methods to solve the systems of equations
2 equations 2 unknowns This calculator has 2 inputs.
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