Use the substitution method to solve:
1c + 2p = 12.40
2c + 3p = 20.20
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
2c + 3p = 20.20
Subtract 3p from both sides to isolate c:
2c + 3p - 3p = 20.20 - 3p
2c = 20.20 - 3p
Now divide by 2:
| 2c | |
| 2 |
| = |
| 20.20 - 3p |
| 2 |
Revised Equation 2:
| c = | 20.20 - 3p |
| 2 |
Plug Revised Equation 2 value into c:
1(c) + 2p = 12.40
1 * ((20.20 - 3p)/2) + 2p = 12.40
((20.2 - 3p)/2) + 2p = 12.40
Multiply equation 1 through by 2
2 * (((20.2 - 3p)/2) + 2p = 12.40)
2 * (((20.2 - 3p)/2) + 2p = 12.40)
20.2 - 3p + 4p = 24.8
Group like terms:
-3p + 4p = 24.8 - 20.2
1p = 4.6
Divide each side by 1
| 1p | |
| 1 |
| = |
| 4.6 |
| 1 |
| p = | 4.6 |
| 1 |
p = 4.6
Plug this answer into Equation 1
1c + 2(4.6) = 12.40
1c + 9.2 = 12.40
1c = 12.40 - 9.2
1c = 3.2
Divide each side by 1
| 1c | |
| 1 |
| = |
| 3.2 |
| 1 |
| c = | 3.2 |
| 1 |
c = 3.2
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