l Use Substitution to solve 2x + y = 35 and 3x + 4y = 65

Enter Equation 1

Enter Equation 2

    

Answer
x = 15 and y = 5


Steps Explained:

Use the substitution method to solve:

3x + 4y = 65

Check Format

Equation 2 is in the correct format.

Rearrange Equation 2 to solve for x:

3x + 4y = 65

Subtract 4y from both sides to isolate x:

3x + 4y - 4y = 65 - 4y

3x = 65 - 4y

Now divide by 3:

3x
3
=
  
65 - 4y
3

Plug Revised Equation 2 value into x:

2(x) + y = 35

2 * ((65 - 4y)/3) + y = 35

((130 - 8y)/3) + y = 35

Multiply equation 1 through by 3

3 * (((130 - 8y)/3) + y = 35)

3 * (((130 - 8y)/3) + y = 35)

130 - 8y + 3y = 105

Group like terms:

-8y + 3y = 105 - 130

-5y = -25

Divide each side by -5

-5y
-5
=
  
-25
-5

y  =  -25
  -5

y = 5

Plug this answer into Equation 1

2x + 1(5) = 35

2x + 5 = 35

2x = 35 - 5

2x = 30

Divide each side by 2

2x
2
=
  
30
2

x  =  30
  2

x = 15



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