Use Substitution to solve 2x + y = 35 and 3x + 4y = 65
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Use the substitution method to solve:
2x + y = 35
3x + 4y = 65
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for x:
3x + 4y = 65
Subtract 4y from both sides to isolate x:
3x + 4y - 4y = 65 - 4y
3x = 65 - 4y
Now divide by 3:
3x
3
=
65 - 4y
3
Revised Equation 2:
x =
65 - 4y
3
Plug Revised Equation 2 value into x:
2(x) + y = 35
2 * ((65 - 4y)/3) + y = 35
((130 - 8y)/3) + y = 35
Multiply equation 1 through by 3
3 * (((130 - 8y)/3) + y = 35)
3 * (((130 - 8y)/3) + y = 35)
130 - 8y + 3y = 105
Group like terms:
-8y + 3y = 105 - 130
-5y = -25
Divide each side by -5
-5y
-5
=
-25
-5
y =
-25
-5
y = 5
Plug this answer into Equation 1
2x + 1(5) = 35
2x + 5 = 35
2x = 35 - 5
2x = 30
Divide each side by 2
2x
2
=
30
2
x =
30
2
x = 15
What is the Answer?
x = 15 and y = 5
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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