Use Elimination to solve 4a + 3c = 40 and 2a + 6c = 38
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Use the elimination method to solve:
4a + 3c = 40
2a + 6c = 38
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Step 1: Multiply Equation 1 by 2:
2 * (4a+3c=40) --> 8a + 6c = 80
Step 2: Multiply Equation 2 by 4:
4 * (2a+6c=38) --> 8a + 24c = 152
Step 3: Equation 1 - Equation 2:
8a + 6c = 80 - (8a + 24c = 152) -(8a + 24c = 152)
6c - 24c = 80 - 152
Step 4: simplify and solve for c:
-18c = -72
c =
-72
-18
c = 4
Step 5: Rearrange Equation 1 to solve for a:
4a = 40 - 3c
Divide each side by 4
4a
4
=
40 - 3c
4
a =
40 - 3c
4
Step 6: Plug c = 4 into equation 1:
a =
40 - 3(4)
4
a =
40 - 12
4
a =
28
4
a = 7
What is the Answer?
a = 7
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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