Enter Simultaneous Equations:

<-- Equation 1
<-- Equation 2

Use the substitution method to solve:

7b + 4c = 8.77

14b + 8c = 15.80

Check Format

Equation 1 is in the correct format.

Check Format

Equation 2 is in the correct format.

Rearrange Equation 2 to solve for b:

14b + 8c = 15.80

Subtract 8c from both sides to isolate b:

14b + 8c - 8c = 15.80 - 8c

14b = 15.80 - 8c

Now divide by 14:

14b
14
=
  
15.80 - 8c
14

Revised Equation 2:

b  =  15.80 - 8c
  14

Plug Revised Equation 2 value into b:

7(b) + 4c = 8.77

7 * ((15.80 - 8c)/14) + 4c = 8.77

((110.6 - 56c)/14) + 4c = 8.77

Multiply equation 1 through by 14

14 * (((110.6 - 56c)/14) + 4c = 8.77)

14 * (((110.6 - 56c)/14) + 4c = 8.77)

110.6 - 56c + 56c = 122.78

Group like terms:

-56c + 56c = 122.78 - 110.6

0c = 12.18

Divide each side by 0

0c
0
=
  
12.18
0

c  =  12.18
  0

Because c = 12.18/0, our system of equations has no solutions