Use the substitution method to solve:
a + s = 324
7a + 3s = 1228
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for a:
7a + 3s = 1228
Subtract 3s from both sides to isolate a:
7a + 3s - 3s = 1228 - 3s
7a = 1228 - 3s
Now divide by 7:
| 7a | |
| 7 |
| = |
| 1228 - 3s |
| 7 |
Revised Equation 2:
| a = | 1228 - 3s |
| 7 |
Plug Revised Equation 2 value into a:
1(a) + s = 324
1 * ((1228 - 3s)/7) + s = 324
((1228 - 3s)/7) + s = 324
Multiply equation 1 through by 7
7 * (((1228 - 3s)/7) + s = 324)
7 * (((1228 - 3s)/7) + s = 324)
1228 - 3s + 7s = 2268
Group like terms:
-3s + 7s = 2268 - 1228
4s = 1040
Divide each side by 4
| 4s | |
| 4 |
| = |
| 1040 |
| 4 |
| s = | 1040 |
| 4 |
s = 260
Plug this answer into Equation 1
1a + 1(260) = 324
1a + 260 = 324
1a = 324 - 260
1a = 64
Divide each side by 1
| 1a | |
| 1 |
| = |
| 64 |
| 1 |
| a = | 64 |
| 1 |
a = 64
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