Use Substitution to solve c + s = 300 and 3c + 1.5s = 825
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Use the substitution method to solve:
c + s = 300
3c + 1.5s = 825
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
3c + 1.5s = 825
Subtract 1.5s from both sides to isolate c:
3c + 1.5s - 1.5s = 825 - 1.5s
3c = 825 - 1.5s
Now divide by 3:
3c
3
=
825 - 1.5s
3
Revised Equation 2:
c =
825 - 1.5s
3
Plug Revised Equation 2 value into c:
1(c) + s = 300
1 * ((825 - 1.5s)/3) + s = 300
((825 - 1.5s)/3) + s = 300
Multiply equation 1 through by 3
3 * (((825 - 1.5s)/3) + s = 300)
3 * (((825 - 1.5s)/3) + s = 300)
825 - 1.5s + 3s = 900
Group like terms:
-1.5s + 3s = 900 - 825
1.5s = 75
Divide each side by 1.5
1.5s
1.5
=
75
1.5
s =
75
1.5
s = 50
Plug this answer into Equation 1
1c + 1(50) = 300
1c + 50 = 300
1c = 300 - 50
1c = 250
Divide each side by 1
1c
1
=
250
1
c =
250
1
c = 250
What is the Answer?
c = 250 and s = 50
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Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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