Use Substitution to solve c + t = 30 and 8c + 12t = 268
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Use the substitution method to solve:
c + t = 30
8c + 12t = 268
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for c:
8c + 12t = 268
Subtract 12t from both sides to isolate c:
8c + 12t - 12t = 268 - 12t
8c = 268 - 12t
Now divide by 8:
8c
8
=
268 - 12t
8
Revised Equation 2:
c =
268 - 12t
8
Plug Revised Equation 2 value into c:
1(c) + t = 30
1 * ((268 - 12t)/8) + t = 30
((268 - 12t)/8) + t = 30
Multiply equation 1 through by 8
8 * (((268 - 12t)/8) + t = 30)
8 * (((268 - 12t)/8) + t = 30)
268 - 12t + 8t = 240
Group like terms:
-12t + 8t = 240 - 268
-4t = -28
Divide each side by -4
-4t
-4
=
-28
-4
t =
-28
-4
t = 7
Plug this answer into Equation 1
1c + 1(7) = 30
1c + 7 = 30
1c = 30 - 7
1c = 23
Divide each side by 1
1c
1
=
23
1
c =
23
1
c = 23
What is the Answer?
c = 23 and t = 7
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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