Use Substitution to solve f + t = 52 and 5f + 10t = 320
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Use the substitution method to solve:
f + t = 52
5f + 10t = 320
Check Format
Equation 1 is in the correct format.
Check Format
Equation 2 is in the correct format.
Rearrange Equation 2 to solve for f:
5f + 10t = 320
Subtract 10t from both sides to isolate f:
5f + 10t - 10t = 320 - 10t
5f = 320 - 10t
Now divide by 5:
5f
5
=
320 - 10t
5
Revised Equation 2:
f =
320 - 10t
5
Plug Revised Equation 2 value into f:
1(f) + t = 52
1 * ((320 - 10t)/5) + t = 52
((320 - 10t)/5) + t = 52
Multiply equation 1 through by 5
5 * (((320 - 10t)/5) + t = 52)
5 * (((320 - 10t)/5) + t = 52)
320 - 10t + 5t = 260
Group like terms:
-10t + 5t = 260 - 320
-5t = -60
Divide each side by -5
-5t
-5
=
-60
-5
t =
-60
-5
t = 12
Plug this answer into Equation 1
1f + 1(12) = 52
1f + 12 = 52
1f = 52 - 12
1f = 40
Divide each side by 1
1f
1
=
40
1
f =
40
1
f = 40
What is the Answer?
f = 40 and t = 12
How does the Simultaneous Equations Calculator work?
Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods: 1) Substitution Method (Direct Substitution) 2) Elimination Method 3) Cramers Method or Cramers Rule
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