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An investment of 6000 was made one year ago.
Part of the investment was placed into an account paying s interest at 8%
The remainder of the investment was placed into an account paying s interest at 6%
After one year, you received a total of 418 in interest. How much was invested in each account?
For Fund 1, we invest an unknown amount, let us call it x
For Fund 2, the remaining principal is 6000 - x
Since Fund 1 credits interest using the simple interest method, we have 0.08x
Since Fund 2 credits interest using the simple interest method, we have 0.06(6000 - x)
Interest Paid | Principal | Interest Rate | |
Fund 1 | 0.08x | x | 8% |
Fund 2 | 0.06(6000 - x) | (6000 - x) | 6% |
Total | 418 | 6000 | -- |
Since both Interest paid columns add up to the total interest earned of 418, we set up an equation
0.08x + 0.06(6000 - x) = 418
0.08x + 360 - 0.06x = 418
360 + 0.02x = 418
360 - 360 + 0.02x = 418 - 360
0.02x = 58
0.02x | |
0.02 |
= |
58 |
0.02 |
x = 2900 ← Fund 1 Investment
This means we should 6000 - 2900 = 3100 into Fund 2