The sum of 4 consecutive numbers equals 27
What are the 4 numbers?
Setup Relational Equation
1) Set up an equation where our numbers are n, n + 1, n + 2, n + 3
2) We increment by 1 for each number since we have numbers.
3) We set this sum of consecutive numbers equal to 27
n + (n + 1) + (n + 2) + (n + 3) = 27
Simplify this equation by grouping variables and constants together:
(n + n + n + n) + 1 + 2 + 3 = 27
4n + 6 = 27
Subtract 6 from each side to isolate 4n:
4n + 6 - 6 = 27 - 6
Cancel the 6 on the left side and we get:
4n + 6 - 6 = 27 - 6
4n = 21
Divide each side of the equation by 4 to isolate n:
| 4n | |
| 4 |
| = |
| 21 |
| 4 |
Cancel the 4 on the left side:
| = |
| 21 |
| 4 |
n = 5.25
Since n is not an integer, there are not 4 consecutive numbers which add up to 27
