Solve the following equation
2b+3+b=60
Solve for b
2b + 3 + b = 60
(2 + 1)b = 3b
3b + 3 = + 60
Group our constants 3 and 60. subtract 3 from both sides
3b + 3 - 3 = 60 - 3
3b = 57
b = 19
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