Solve the following equation
3s+15=57
Solve for s
3s + 15 = 57
Divide each side by 3
| 3s | |
| 3 |
| = |
| 15 |
| 3 |
Group constants
Group our constants 15 and 57.
subtract 15 from both sides
3s + 15 - 15 = 57 - 15
Cancel 15 on the left side:
3s = 42
Divide each side of the equation by 3
| 3s | |
| 3 |
| = |
| 42 |
| 3 |
s = 14
Final Answer
s = 14
