Solve the following equation
b+b+3=35
Solve for b
b + b + 3 = 35
(1 + 1)b = 2b
2b + 3 = + 35
Group our constants 3 and 35. subtract 3 from both sides
2b + 3 - 3 = 35 - 3
2b = 32
b = 16
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