Solve the following equation
d+2+d=8
Solve for d
d + 2 + d = 8
(1 + 1)d = 2d
2d + 2 = + 8
Group our constants 2 and 8. subtract 2 from both sides
2d + 2 - 2 = 8 - 2
2d = 6
d = 3
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